Laboratory Instruments

A laboratory centrifuge 0.20 m in diameter rotates at a rate of 6,000 rpm (revolution per minute) which means the time per revolution is 0.01 s. What is the speed (in m/s) of a point on the outer rim of the centrifuge?
Thanks!

2 Comments zu “Physics Problem On Speed/acceleration?”

1. magesha
   2-8-2010 @ 07:01

   The previous answer is good, except:
   Velocity = omega * r (not omega * Dia)
   rps = 100
   omega = 2 * 3.142 * 100 (rps) = 628.4
   r = dia /2 = 0.1 m
   velocity = 628.4 * 0.1 = 62.84 m/s

   
   

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2. Paras B
   2-8-2010 @ 11:30

   rps = 100
   omega = 2*3.14*100 = 628 rad/sec
   v=628 * 0.20 m/s =125.6 m/s

   
   

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